Kangaroo - mathematics for everyone. International mathematical competition-game “Kangaroo”

March 16, 2017 Grades 3–4. The time allotted for solving problems is 75 minutes!

Problems worth 3 points

№1. Kanga made five addition examples. What is the largest amount?

(A) 2+0+1+7 (B) 2+0+17 (C) 20+17 (D) 20+1+7 (E) 201+7

№2. Yarik marked the path from the house to the lake with arrows on the diagram. How many arrows did he draw incorrectly?

(A) 3 (B) 4 (C) 5 (D) 7 (E) 10

№3. The number 100 was increased by one and a half times, and the result was reduced by half. What happened?

(A) 150 (B) 100 (C) 75 (D) 50 (E) 25

№4. The picture on the left shows beads. Which picture shows the same beads?

№5. Zhenya composed six three-digit numbers from the numbers 2.5 and 7 (the numbers in each number are different). Then she arranged these numbers in ascending order. What number was the third?

(A) 257 (B) 527 (C) 572 (D) 752 (E) 725

№6. The picture shows three squares divided into cells. On the outer squares, some of the cells are painted over, and the rest are transparent. Both of these squares were superimposed on the middle square so that their upper left corners coincided. Which of the figures is still visible?

№7. What is the most small number Should the white cells in the picture be painted over so that there are more colored cells than white ones?

(A) 1 (B) 2 (C) 3 (D) 4 (E)5

№8. Masha drew 30 geometric shapes in this order: triangle, circle, square, rhombus, then again triangle, circle, square, rhombus and so on. How many triangles did Masha draw?

(A) 5 (B) 6 (C) 7 (D) 8 (E)9

№9. From the front, the house looks like the picture on the left. At the back of this house there is a door and two windows. What does it look like from behind?

№10. It's 2017 now. How many years from now will the next year be that does not have the number 0 in its record?

(A) 100 (B) 95 (C) 94 (D) 84 (E)83

Objectives, assessment worth 4 points

№11. Balls are sold in packs of 5, 10 or 25 pieces each. Anya wants to buy exactly 70 balls. What is the smallest number of packages she will have to buy?

(A) 3 (B) 4 (C) 5 (D) 6 (E) 7

№12. Misha folded a square piece of paper and poked a hole in it. Then he unfolded the sheet and saw what is shown in the picture on the left. What might the fold lines look like?

№13. Three turtles sit on the path at points A, IN And WITH(see picture). They decided to gather at one point and find the sum of the distances they had traveled. What is the smallest amount they could get?

(A) 8 m (B) 10 m (C) 12 m (D) 13 m (E) 18 m

№14. Between the numbers 1 6 3 1 7 you need to insert two characters + and two signs × so that you get the biggest result. What is it equal to?

(A) 16 (B) 18 (C) 26 (D) 28 (E) 126

№15. The strip in the figure is made up of 10 squares with a side of 1. How many of the same squares must be added to it on the right so that the perimeter of the strip becomes twice as large?

(A) 9 (B) 10 (C) 11 (D) 12 (E) 20

№16. Sasha marked a square in the checkered square. It turned out that in its column this cell is the fourth from the bottom and the fifth from the top. In addition, in its row this cell is the sixth from the left. Which one is she on the right?

(A) second (B) third (C) fourth (D) fifth (E) sixth

№17. From a 4 × 3 rectangle, Fedya cut out two identical figures. What kind of figures could he not produce?

№18. Each of the three boys thought of two numbers from 1 to 10. All six numbers turned out to be different. The sum of Andrey’s numbers is 4, Bory’s is 7, Vitya’s is 10. Then one of Vitya’s numbers is

(A) 1 (B) 2 (C) 3 (D) 5 (E)6

№19. Numbers are placed in the cells of a 4 × 4 square. Sonya found a 2 × 2 square in which the sum of the numbers is the largest. What is this amount?

(A) 11 (B) 12 (C) 13 (D) 14 (E) 15

№20. Dima was riding a bicycle along the paths of the park. He entered the park through the gate A. During his walk, he turned right three times, left four times, and turned around once. What gate did he go through?

(A) A (B) B (C) C (D) D (E) the answer depends on the order of turns

Tasks worth 5 points

№21. Several children took part in the race. The number of people who came running before Misha was three times more number those who came running after him. And the number of those who came running before Sasha is two times less than the number of those who came running after her. How many children could take part in the race?

(A) 21 (B) 5 (C) 6 (D) 7 (E) 11

№22. Some shaded cells contain one flower. Each white cell contains the number of cells with flowers that have a common side or top with it. How many flowers are hidden?

(A) 4 (B) 5 (C) 6 (D) 7 (E) 11

№23. We will call a three-digit number amazing if among the six digits used to write it and the number following it, there are exactly three ones and exactly one nine. How many amazing numbers are there?

(A) 0 (B) 1 (C) 2 (D) 3 (E) 4

№24. Each face of the cube is divided into nine squares (see picture). What is the most large number Can squares be colored so that no two colored squares have a common side?

(A) 16 (B) 18 (C) 20 (D) 22 (E) 30

№25. A stack of cards with holes is strung on a string (see picture on the left). Each card is white on one side and shaded on the other. Vasya laid out the cards on the table. What could he have done?

№26. A bus leaves from the airport to the bus station every three minutes and takes 1 hour. 2 minutes after the bus departed, a car left the airport and drove 35 minutes to the bus station. How many buses did he overtake?

(A) 12 (B) 11 (C) 10 (D) 8 (E) 7

We present tasks and answers to the Kangaroo 2015 competition for 2 grades.
Answers to Kangaroo 2015 tasks are found after the questions.

Problems worth 3 points
1. Which letter is missing in the pictures on the right to form the word KANGAROO?

Possible answers:
(A) G (B) E (C) K (D) N (D) R

2. After Sam climbed the third step of the stairs, he began to step one step at a time. What step will he be on after three such steps?
Possible answers:
(A) 5 (B) 6 (C) 7 (D) 9 (E) 11

3. The picture shows a pond and several ducks. How many of these ducks are swimming in the pond?

Possible answers:

4. Sasha walked twice as long as she did her homework. She spent 50 minutes on the lessons. How long did she walk?
Possible answers:
(A) 1 hour (B) 1 hour 30 minutes (C) 1 hour 40 minutes (D) 2 hours (E) 2 hours 30 minutes

5. Masha drew five portraits of her favorite nesting doll, but she made a mistake in one drawing. Which one?

6. What is the number indicated by the square?

Possible answers:
(A) 2 (B) 3 (C) 4 (D) 5 (E) 6

7. Which of the figures (A)–(D) cannot be made from the two bars shown on the right?

8. Seryozha thought of a number, added 8 to it, subtracted 5 from the result and got 3. What number did he think of?
Possible answers:
(A) 5 (B) 3 (C) 2 (D) 1 (E) 0

9. Some of these kangaroos have a neighbor who faces in the same direction. How many kangaroos have such a neighbor?


Possible answers:

10. If yesterday was Tuesday, then the day after tomorrow will be
Possible answers:
(A) Friday (B) Saturday (C) Sunday (D) Wednesday (E) Thursday

Problems worth 4 points

11. What is the smallest number of figures that will have to be removed so that only figures of the same type remain?

Possible answers:
(A) 9 (B) 8 (C) 6 (D) 5 (E) 4

12. There were 6 square chips in a row. Between every two adjacent chips, Sonya placed a round chip. Then Yarik placed a triangular chip between each adjacent chips in the new row. How many chips did Yarik put in?
Possible answers:
(A) 7 (B) 8 (C) 9 (D) 10 (E) 11

13. The arrows in the figure indicate the results of actions with numbers. The numbers 1, 2, 3, 4 and 5 must be placed one at a time in the squares so that all the results are correct. What number will be in the shaded square?

Possible answers:
(A) 1 (B) 2 (C) 3 (D) 4 (E) 5

14. Petya drew a line on a sheet of paper without lifting his pencil from the paper. Then he cut this sheet into two parts. The upper part is shown in the figure on the right. What might the bottom of this sheet look like?

15. Little Fedya writes down numbers from 1 to 100. But he doesn’t know the number 5 and misses all the numbers that contain it. How many numbers will he write down?
Possible answers:
(A) 65 (B) 70 (C) 72 (D) 81 (E) 90

16. The pattern on the tiled wall consisted of circles. One of the tiles fell out. Which?

17. Petya arranged 11 identical pebbles into four piles so that all piles contained different number pebbles. How many pebbles are in the largest pile?
Possible answers:
(A) 4 (B) 5 (C) 6 (D) 7 (E) 8

18. On the right is the same cube in different positions. It is known that a kangaroo is drawn on one of its faces. What figure is drawn opposite this face?

19. The Goat has seven kids. Five of them already have horns, four have spots on the skin, and one has neither horns nor spots. How many kids have both horns and spots on their skin?
Possible answers:
(A) 1 (B) 2 (C) 3 (D) 4 (E) 5

20. Kostya has white and black cubes. He built 6 towers of 5 cubes each so that the colors of the cubes alternate in each tower. The picture shows what its structure looks like from above. How many black cubes did Kostya use?

Possible answers:
(A) 4 (B) 10 (C) 12 (D) 16 (E) 20

Tasks worth 5 points

21. In 16 years, Dorothy will be 5 times older than she was 4 years ago. In how many years will she be 16?
Possible answers:
(A) 6 (B) 7 (C) 8 (D) 9 (E) 10

22. Sasha pasted five round stickers with numbers on a sheet of paper one after another (see picture). In what order could she paste them?

Possible answers:
(A) 1, 2, 3, 4, 5 (B) 5, 4, 3, 2, 1 (C) 4, 5, 2, 1, 3 (D) 2, 3, 4, 1, 5 (E ) 4, 1, 3, 2, 5

23. The figure shows the front, left and top views of a structure made of cubes. Which greatest number Can there be cubes in this design?

Possible answers:
(A) 28 (B) 32 (C) 34 (D) 39 (E) 48

24. How many exist three-digit numbers, for which any two adjacent digits differ by 2?
Possible answers:
(A) 22 (B) 23 (C) 24 (D) 25 (E) 26

25. Vasya, Tolya, Fedya and Kolya were asked if they would go to the cinema.
Vasya said: “If Kolya doesn’t go, then I will go.”
Tolya said: “If Fedya goes, then I won’t go, but if he doesn’t go, then I will go.”
Fedya said: “If Kolya doesn’t go, then I won’t go either.”
Kolya said: “I will only go with Fedya and Tolya.”
Which of the guys went to the cinema?
Possible answers:

A) Fedya, Kolya and Tolya (B) Kolya and Fedya (C) Vasya and Tolya (D) only Vasya (D) only Tolya

Answers Kangaroo 2015 - 2nd grade:
1. A
2. G
3. B
4. B
5. D
6. D
7. B
8. D
9. G
10. A
11. A
12. G
13. D
14. D
15. G
16.V
17. B
18. A
19. B
20. G
21. B
22. 22
23. B
24. D
25.V

Competition "Kangaroo" is an Olympiad for all schoolchildren from grades 3 to 11. The purpose of the competition is to get children interested in solving mathematical problems. The competition tasks are very interesting, all participants (both strong and weak in mathematics) find exciting problems for themselves.

The competition was invented by Australian scientist Peter Halloran in the late 80s of the last century. "Kangaroo" quickly gained popularity among schoolchildren in different corners Earth. In 2010, more than 6 million schoolchildren from approximately fifty countries took part in the competition. The geography of participants is very extensive: European countries, USA, countries Latin America, Canada, Asian countries. The competition has been held in Russia since 1994.

Competition "Kangaroo"

The Kangaroo competition is annual and is always held on the third Thursday of March.

Schoolchildren are asked to solve 30 tasks of three levels of difficulty. Points are awarded for each correctly completed task.

The Kangaroo competition is paid, but its price is not high; in 2012 you had to pay only 43 rubles.

The Russian organizing committee of the competition is located in St. Petersburg. The competition participants send all answer forms to this city. Answers are checked automatically - on a computer.

The results of the Kangaroo competition are released to schools at the end of April. The winners of the competition receive diplomas, and the remaining participants receive certificates.

Personal results of the competition can be found out faster - in early April. To do this you need to use a personal code. The code can be obtained on the website http://mathkang.ru/

How to prepare for the Kangaroo competition

Peterson's textbooks contain problems that were used in previous years at the Kangaroo competition.

On the Kangaroo website you can see problems with answers that were given in previous years.

And for better preparation, you can use books from the “Kangaroo Mathematical Club Library” series. These books tell entertaining stories about mathematics in a fun way and include interesting mathematical games. Problems that were presented in past years at a mathematical competition are analyzed, and innovative ways to solve them are given.

Mathematical club "Kangaroo", issue No. 12 (grades 3-8), St. Petersburg, 2011

I really liked the book called “The Book of Inches, Tops and Centimeters.” It tells about how units of measurement arose and developed: pieds, inches, cables, miles, etc.

Mathematical club "Kangaroo"

Let me give you some interesting stories from this book.

At V.I. Dahl, an expert on the Russian people, has this entry: “As for the city, so is the faith; as for the village, so is the measure.”

For a long time, in different countries Various measurement measures were used. So, in ancient China for men's and women's clothing Various measures were used. For men they used “duan”, which was 13.82 meters, and for women they used “pi” - 11.06 meters.

IN everyday life measures varied not only between countries, but also between cities and villages. For example, in some Russian villages the measure of duration was the time “until a pot of water boils.”

Now solve problem number 1.

Old clocks are 20 seconds slower every hour. The hands are set to 12 o'clock, what time will the clock show in a day?

Problem No. 2.

At the pirate market, a barrel of rum costs 100 piastres or 800 doubloons. A pistol costs 250 ducats or 100 doubloons. The seller asks for 100 ducats for the parrot, but how many piastres will it be?

Mathematical club "Kangaroo", children's mathematical calendar, St. Petersburg, 2011

In the “Kangaroo Library” series, a mathematical calendar is published, in which there is one task for each day. By solving these problems, you can give excellent food to your brain, and at the same time prepare for the next Kangaroo competition.

Mathematical club "Kangaroo"

Ben chose a number, divided it by 7, then added 7 and multiplied the result by 7. The result was 77. What number did he choose?

An experienced trainer washes an elephant in 40 minutes, and his son takes 2 hours. If two of them wash the elephants, how long will it take them to wash three elephants?

Mathematical club "Kangaroo", issue No. 18 (grades 6-8), St. Petersburg, 2010

This issue features combinatorial problems from the branch of mathematics that studies various relationships in finite sets of objects. Combinatorial problems occupy a large part in mathematical entertainment: games and puzzles.

Kangaroo Club

Problem No. 5.

Count how many ways are there to place a white and a black rook on a chessboard without them killing each other?

This is the most difficult task, so I will give its solution here.

Each rook holds under attack all the cells of the vertical and horizontal lines on which it stands. And she occupies another cell herself. Therefore, 64-15=49 remains on the board free cells, on each of which you can safely place a second rook.

Now it remains to note that for the first (for example, white) rook we can choose any of the 64 cells of the board, and for the second (black) - any of the 49 cells, which after this will remain free and will not be under attack. This means we can apply the multiplication rule: total quantity options for the required arrangement is 64*49=3136.

When solving this problem, it helps that the very condition of the problem (everything happens on the chessboard) helps to visualize possible options relative position figures. If the conditions of conception are not so clear, you need to try to make them clear.

I hope you enjoyed getting to know math competition"Kangaroo" .

The Kangaroo competition has been held since 1994. It originated in Australia on the initiative of the famous Australian mathematician and educator Peter Halloran. The competition is designed for ordinary schoolchildren and therefore quickly won the sympathy of both children and teachers. The competition tasks are designed so that each student finds interesting and accessible questions for himself. After all main goal of this competition is to interest the children, to instill in them confidence in their abilities, and the motto is “Mathematics for everyone.”

Now about 5 million schoolchildren around the world participate in it. In Russia, the number of participants exceeded 1.6 million people. In the Udmurt Republic, 15-25 thousand schoolchildren annually participate in Kangaroo.

In Udmurtia, the competition is held by the Center educational technologies"Another school."

If you are in another region of the Russian Federation, contact the central organizing committee of the competition - mathkang.ru

Procedure for holding the competition

The competition is held in test form in one stage without any preliminary selection. The competition is held at school. Participants are given tasks containing 30 problems, where each problem is accompanied by five answer options.

All work is given 1 hour 15 minutes of pure time. Then the answer forms are submitted and sent to the Organizing Committee for centralized verification and processing.

After verification, each school that took part in the competition receives a final report indicating the points received and the place of each student in the general list. All participants are given certificates, and parallel winners receive diplomas and prizes; the best ones are invited to math camps.

Documents for organizers

Technical documentation:

Instructions for holding a competition for teachers.

Form for the list of participants in the "KANGAROO" competition for school organizers.

Form of Notification of informed consent of competition participants (their legal representatives) for the processing of personal data (filled out by the school). Their completion is necessary due to the fact that the personal data of competition participants is automatically processed using computer technology.

For organizers who want to additionally insure themselves regarding the validity of collecting a registration fee from participants, we offer the form of the Minutes of the Parent Community Meeting, the decision of which will also confirm the powers of the school organizer on the part of the parents. This is especially true for those who plan to act as an individual.

Constructions and logical reasoning.

Problem 19. winding coast (5 points) .
The picture shows an island on which a palm tree grows and several frogs sit. The island is limited coastline. How many frogs are sitting on the ISLAND?

Answer options:
A: 5; B: 6; IN: 7; G: 8; D: 10;

Solution
To solve this problem on your computer, you can use the Paint Fill tool. Now you can clearly see that there are 6 frogs sitting on the island.

You could have done something similar to this fill with a pencil on a sheet of conditions. But there's another one interesting way, which allows you to determine whether a point is inside or outside a closed non-self-intersecting curve.

Let's connect this point (frog) with a point that we know for sure is outside the curve. If the connecting line has an odd number of intersections with the curve, then our point lies inside (i.e. on the island), and if it has an even number, then outside (on the water)

Correct answer: B 6

Problem 20. Numbers on the balls (5 points) .
Mudragelik has 10 balls, numbered from 0 to 9. He divided these balls between his three friends. Lasunchik received three balls, Krasunchik - four, Sonya O- three. Then Mudragelik asked each of his friends to multiply the numbers on the balls they received. Lasunchik received a product equal to 0, Krasunchik - 72, and Sonya O- 90. All the kangaroos multiplied the numbers correctly. What is the sum of the numbers on the balls that Lasunchik received?

Answer options:
A: 11; B: 12; IN: 13; G: 14; D: 15;

Solution
It is clear that among the three balls that Lasunchik received, there is the number 0. It remains to find 2 more numbers. Krasunchik has as many as 4 balls, so it will be easier to first find which three numbers from 1 to 9 need to be multiplied to get 90, like Sonya A? 90 = 9x10 = 9x2x5. This will be the only way to represent 90 as a product of the numbers on the balls. After all, if Sonya A one of the balls was with a unit, then 90 would have to be divided into the product of two factors less than 10, which is impossible.

So, Lasunchik has 0 and two other balls, Sonya has A balls 2, 5, 9.
Handsome's four balls give the product of 72. Let's first break 72 into the product of two factors, so that we can then divide each of these factors into 2 more:
72 = 1x72 = 2x36 = 3x24 = 4x18 = 6x12 = 8x9

From these options we immediately cross out:
1x72 - because we cannot split 1 into 2 different factors
2x36 - because 2 breaks only like 1x2, but Krasunchik definitely doesn’t have a ball with the number 2
8x9 - because 9 is broken like 1x9 (it can’t be broken like 3x3, since there are no two balls with threes), and Red doesn’t have a nine either

Options remain:
3x24 - divided into 4 factors like 1x3x4x6
4x18 - divided into 4 factors as 1x4x3x6, that is, the same as the first option
6x12 - breaks like 1x6x3x4 (after all, let us remind you that there is no ball with a deuce).

So, for Red's set of balls there is only one option. He has balls 1, 3, 4, 6.

For Lasunchik, in addition to the ball with the number 0, there are still balls 7 and 8. Their sum is 15

Correct answer: D 15

Problem 21. Ropes (5 points) .
Three ropes are attached to the board as shown in the figure. You can attach three more to them and get a complete loop. Which of the ropes given in the answers will make it possible to do this?
According to group "Kangaroo" VKontakte, this problem was correctly solved by only 14.6% of the participants in the Mathematical Olympiad from the third and fourth grades.

Answer options:
A: ; B: ; IN: ; G: ; D: ;

Solution
This problem can be solved by mentally attaching picture to picture and carefully checking the connections. Or you can do things a little better. Let's renumber the ropes and write down line 123132 - these are the ends of the loops in the figure given in the condition. Now we also sign these numbers above the ends of the ropes in the answer options.

Now it's easy to see what's in the option A rope 2 connects to itself. In option B rope 1 is connected to itself. But in the variant IN All ropes are connected to each other into one large loop.

Correct answer: B
Problem 22. Elixir Recipe (5 points) .
To prepare the elixir, you need to mix five types of aromatic herbs, the mass of which is determined by the balance of the scales shown in the figure (we neglect the mass of the scales themselves). The healer knows that he needs to put 5 grams of sage in the elixir. How many grams of chamomile should he take?

Answer options:
A: 10 g; B: 20 g; IN: 30 g; G: 40 g; D: 50 g;

Solution
You need to take the same amount of basil as sage, that is, also 5 grams. There is as much mint as sage and basil together (by convention, we do not take into account the mass of the scales themselves). This means you need to take 10 grams of mint. You need to take as much lemon balm as mint, sage and basil, that is, 20g. And chamomile - as much as all the previous herbs, 40 g.

Correct answer: G 40g

Problem 23. Unseen beasts (5 points) .
Tom drew a pig, a shark and a rhinoceros on the cards and cut each card as shown. Now he can stack different "animals" by connecting one head, one middle and one back. How many different fantasy creatures can Tom collect?

Answer options:
A: 3; B: 9; IN: 15; G: 27; D: 20;

Solution
This is a classic combinatorics problem. The good thing is that they can (and should) be solved not by mechanically applying the rules for calculating the numbers of permutations and combinations, but by reasoning. How many different options is there one for the animal's head? Three options. And for the middle part? Also three. There are three options for the tail. This means that there will be a total of 3x3x3 = 27 different options. We multiply these options because any body and any tail can be attached to each head, so that each segment of the animal increases the combination options by 3 times.

By the way, the condition contains the word “fantastic”. But by combining any heads, torsos and tails, we will get a real pig, shark and rhinoceros. So the correct answer should have been 24 fantasy animals and three real ones. However, apparently fearing different interpretations conditions, the authors did not include option 24 in the answers. Therefore, we choose answer D, 27. And who knows, what if the pictures also depict a fantastic talking pig, a fantastic flying shark and a fantastic rhinoceros that proved Fermat’s theorem? :)

Correct answer: G 27

Problem 24. Kangaroo bakers (5 points) .
Mudragelik, Lasunchik, Krasunchik, Khitrun and Sonko baked cakes on Saturday and Sunday. During this time, Mudragelik baked 48 cakes, Lasunchik – 49, Krasunchik – 50, Khitrun – 51, Sonko – 52. It turned out that on Sunday each little kangaroo baked more cakes than on Saturday. One of them sintered twice as much, one - 3 times, one - 4 times, one - 5 times, and one - 6 times.
Which of the kangaroos baked the most cakes on Saturday?

Answer options:
A: Mudragelik; B: Lasunchik; IN: Pretty; G: Hitrun; D: Sonko;

Solution
Let's first think about what information does the fact that someone baked exactly 2 times more cakes on Sunday than on Saturday give us? If on Saturday the kangaroo baked a number of cakes, then on Sunday - so many and so many more. This means that in just two days he baked three times (1+2 = 3) more cakes than on Saturday.

So what? And the fact that, for example, he couldn’t bake 49 or cakes like these.

It turns out that for someone who baked three times as many cakes on Sunday as on Saturday, their total number should increase by 4 = 1+3. Some people have 5, some have 6 and some have 7.

The principle for solving this problem emerges. Here we have five numbers: 48, 49, 50, 51, 52. 3 of them are divisible by 2 numbers (48 and 51) and 4 are divisible by 2 numbers (48 and 52). But only one number is divisible by 5, 50. It turns out that the one who baked 50 pies baked 4 times more on Sunday than on Saturday.

There is also only one number divisible by 6, this is 48. It turns out that the little kangaroo who baked only 48 cakes baked them like this: 8 on Saturday and 40 on Sunday. Well, then it’s simple. We get that:
Mudragelik baked 48 cakes: 8 on Saturday and 40 on Sunday (5 times more)
Lasunchik baked 49 cakes: 7 on Saturday and 42 on Sunday (6 times more)
Pretty baked 50 cakes: 10 on Saturday and 40 on Sunday (4 times more)
Hitrun baked 51 cakes: 17 on Saturday and 34 on Sunday (2 times more)
Sonko baked 52 cakes: 13 on Saturday and 39 on Sunday (3 times more)

It turns out that on Saturday, Hitrun bakes the most cakes.

Correct answer: G Hitrun